From: John Evans Subject: My version of counting objects. This is a simple drop-in tid-bit of code that returns the number of items that someone is in possession of. It counts through containers recursively so that if someone puts 14 things in a sack that is put in a sack that is put in a sack that is put in a sack that is put in a sack that is put in a sack that is put in a sack, it will still count the 14 items and all of the sacks. ---------- File: utils.h ---------- int item_count(struct char_data *ch); ---------- File: utils.c ---------- /* Will return the number of items in the container. */ int count_contents(struct obj_data *container) { int count = 0; struct obj_data *obj; if (container->contains) for (obj = container->contains; obj; obj = obj->next_content, count++) if (GET_OBJ_TYPE(obj) == ITEM_CONTAINER && obj->contains) count += count_contents(obj); return(count); } /* Will return the number of items that the character owns. */ int item_count(struct char_data *ch) { int i, count = 0; struct obj_data *obj; for (i = 0; i < NUM_WEARS; i++) { if (GET_EQ(ch, i)) { count++; if (GET_OBJ_TYPE(GET_EQ(ch, i)) == ITEM_CONTAINER && GET_EQ(ch, i)->contains) count += count_contents(GET_EQ(ch, i)); } } if (ch->carrying) for (obj = ch->carrying; obj; obj = obj->next_content, count++) if (GET_OBJ_TYPE(obj) == ITEM_CONTAINER && obj->contains) count += count_contents(obj); return(count); } That allows you to do something similar to the following in do_score(): sprintf(buf, "You possess %d items.\r\n", item_count(ch)); send_to_char(buf, ch); Easy enough, eh? John Evans