On Fri, 17 Jan 1997 BuckFloyd@aol.com wrote:
- > if (number(0,100) > number(0, 100))
- > {
- > if ((number(0, 100) < 50) && (number(0, 100) > 85))
- > {
Wow that really is odd. To each his or her own, I guess, but it's a
little wasteful of processor time. I think somoene who's had a statistics
class could break those 4 random numbers down and turn it into one.
This is my take on it:
- > if (number(0,100) > number(0, 100))
This looks like a 50-50 chance to me, which could be changed to:
if(number(0, 1))
And add these in:
- > if ((number(0, 100) < 50) && (number(0, 100) > 85))
Hmm another 50-50, and a %15 chance. Since these are all and'ed together,
if my wild guess at statistics is correct, you've got a 50/100 + 50/100 +
15/100 chance of getting through all the ifs, or 115/300, or a 38%. Am I
close? If so, then you could consolidate all four random number
generators into this one line:
if(!number(0, 37))
Sam
p.s. Yeah I know my numbers aren't exact, it's the formula I'm wondering
about :P
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